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الكلية كلية العلوم
القسم قسم الفيزياء
المرحلة 2
أستاذ المادة فؤاد حمزة عبد الشريفي
22/03/2019 14:55:03
The general 2nd order linear PDE The general second order linear PDE has the following form Au_xx+Bu_xy+Cu_yy+Du_x+Eu_y+Fu=G where the coefficients A,B,C,D,E,F and G are in general functions of the independent variables x,y, but do not depend on the unknown function u. In this lecture we discuss only four cases as follows: (1) When B=C=E=F=0 the PDE becomes Au_xx+Du_x=G (2) When A=C=E=F=0 the PDE becomes Bu_xy+Du_x=G (3) When A=C=D=F=0 the PDE becomes Bu_xy+Eu_y=G (4) When A=B=D=F=0 the PDE becomes Cu_yy+Eu_y=G We can solve the PDE by assuming that v=u_x in cases (1)& (2) and v=u_y in cases (3)& (4). Then the PDE becomes linear ODE. The following examples explain how to solve the PDE. Example 1: Solve u_xx-yu_x=2y with u(1,y)=-2 and u_x (0,y)=y-2 Solution? Put u_x=v ? u_xx=dv/dx So dv/dx-yv=2y Which is a linear ODE with P(x)=-y and Q(x)=2y So,the integrating factor is I.F=e^??? P(x)dx?=e^(???-y? dx)=e^(-yx) Then v=1/(I.F) ???I.F ? Q(x)dx ? v=1/e^(-yx) ???e^(-yx) ? 2y dx v=e^yx (-2e^(-yx)+f(y)) ? v=-2+e^yx f(y) u_x=v ? u_x=-2+e^yx f(y) u_x (0,y)=y-2 ? y-2=-2+f(y) ? f(y)=y u_x=-2+ye^yx u(x,y)=??(-2+ye^yx )dx=-2x+e^yx+g(y) u(1,y)=-2 ? -2=-2+e^y+g(y) ? g(y)=e^y Then u(x,y)=-2x+e^yx+e^y Example 2: Solve u_xy+u_x=1 with u(0,y)=0 and u_x (x,0)=sin?x Solution?Put u_x=v ? u_xy=dv/dy ? dv/dy+v=1 Which is a linear ODE with P(y)=1 and Q(y)=1 So,the integrating factor is I.F=e^??? P(y)dy?=e^??dy=e^y Then v=1/(I.F) ???I.F ? Q(y)dy ? v=e^(-y) ???e^y ? dy v=e^(-y) (e^y+f^ (x)) ? v=1+e^(-y) f(x) ? u_x=1+e^(-y) f(x) u_x (x,0)=sin?x ? sin?x=1+f(x) ? f(x)=-1+sin?x Then u(x,y)=??(1+e^(-y) (-1+sin?x )) dx=??(1-e^(-y)+e^(-y) sin?x ) dx u(x,y)=x-xe^(-y)-e^(-y) cos?x+g(y) u(0,y)=0 ? g(y)=e^(-y) u(x,y)=x-xe^(-y)-e^(-y) cos?x+e^(-y) Example 3: Solve xu_xy+2u_y=9y^2 x with u_y (1,y)=0 and u(x,0)=1 Solution? Put u_y=v ? u_xy=dv/dx xu_xy+2u_y=y^2? x dv/dx+2v=9y^2 x ? dv/dx+( 2 )/x v=9y^2 I.F=e^??? P(x)dx?=e^(??( 2 )/x dx)=e^(2 ln?x )=e^ln??x^2 ? =x^2 v=1/x^2 ???9x^2 ? y^2 dx=1/x^2 (3x^3 y^2+f(y)) ? u_y=3xy^2+1/x^2 f(y) u_y (1,y)=0 ? f(y)=-3y^2 u_y=3xy^2-(3y^2)/x^2 u(x,y)=??(3xy^2-(3y^2)/x^2 ) dy=xy^3+y^3/x^2 +g(x) u(x,0)=1 ? g(x)=1 u(x,y)=xy^3+y^3/x^2 +1 Example 4:Solve u_yy+2u_y=2 sin?x with u(x,0)=0 and u_y (x,0)=3 sin?x Solution? Put u_y=v ? u_yy=dv/dy dv/dy+2v=2 sin?x I.F=e^??? P(y)dy?=e^??2dy=e^2y v=e^(-2y) ???2e^2y ? sin?x dy u_y=e^(-2y) (e^2y sin?x+f(x))=sin?x+e^(-2y) f(x) u_y (x,0)=3 sin?x ? 3 sin?x=sin?x+f(x) ? f(x)=2 sin?x u_y=sin?x+2 sin?x e^(-2y) Then u(x,y)=??(sin?x+2 sin?x e^(-2y) ) dy u(x,y)=y sin?x-sin?x e^(-2y)+g(x) u(x,0)=0? g(x)=sin?x u(x,y)=y sin?x-sin?x e^(-2y)+sin?x=sin?x (y-e^(-2y)+1)
H.W: Solve the PDE 1. u_xx+3u_x=3e^y with u(1,y)=( 2 )/( 3 ) e^(y-3) and u_x (0,y)=2e^y 2. u_xy-u_x=2 with u(0,y)=tan?y and u_x (x,0)=sec^2?x-2 3. xu_xy+u_y=0 with u_y (1,y)=cos?y and u(x,( ? )/( 2 ))=0 4. u_yy-u_y=tan^(-1)?x with u(x,0)=0 and u_y (x,0)=0
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